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请求错误时 ApiException的handleException方法有问题 #5

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@1335987402

if (!apiResult.isSuccess()) {
Log.e("----------------","getResultCode="+apiResult.getResultCode());
throw new ServerException(apiResult.getResultMsg(), apiResult.getResultCode());
}
当我请求错误时,没有弹出我的msg 而是在ApiException中的handleException方法里面走的else 为什么没有走else if (e instanceof ServerException) 需要怎么才走这个

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