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MrFatt
LintCodeInPython
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candy.py
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candy.py
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# -*- coding: utf-8 -*-
class Solution:
# @param {int[]} ratings Children's ratings
# @return {int} the minimum candies you must give
def candy(self, ratings):
# Write your code here
'''
题目的表达有问题,并不是等级越高糖越多。
比如[1, 2, 2]的情况,
因为当中的2比1大,所以分2块,而最右边的2只是和左边的2相等,所以只分1块。
思路如下:
1. 初始化每人至少1颗糖。
2. 从左向右遍历,如果比前面等级高,那么比前面多分一粒糖。
3. 从右往左遍历,如果比后面等级高,并且不比后面的糖多,那么比后面多分一粒糖。
'''
if not ratings:
return 0
candies = [1 for i in xrange(len(ratings))]
for i in xrange(1, len(ratings)):
if ratings[i] > ratings[i - 1]:
candies[i] = candies[i - 1] + 1
for i in xrange(len(ratings) - 2, -1, -1):
if ratings[i] > ratings[i + 1]:
if candies[i] <= candies[i + 1]:
candies[i] = candies[i + 1] + 1
return sum(candies)
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