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118 changes: 118 additions & 0 deletions research/gaussian-tensor-error/README.md
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# The factor (10 p^2)^g is absorbed by the same gate

**Claim type:** an explicit absorption bound for one tensor error.
**No new κ.** The per-axis ceiling `10 p^2` stays a hypothesis. The selected
record remains `23/10000`.

## Question

#4482 leaves HALO's tensor error as `g p^{10 g} exp(-p^2)`. The open step is
to replace `p^{10}` by the inverse ceiling `10 p^2` and ask whether
`g log p = o(p)` still puts the error below `2^{-C p}` for every fixed `C`.

## Lemma

Let `p ≥ 2`, `g ≥ 1`, `K ≥ 0` and `C ≥ 0` be integers, and let
`L = ceil(log2 p)`. If

```text
p ≥ max(64, 4K + 2C) and 16 g L ≤ p,
```

then

```text
g (10 p^2)^g exp(K p - p^2) < 2^{-C p}.
```

Thus a global factor `exp(K p)` does not change the conclusion. Whenever
`g log p = o(p)`, every fixed pair `K, C` satisfies the gate for all large
`p`. The exponent 10 is not required for this absorption.

The gate is not optional for every `g`. At `g = p^2` the same substituted
error is greater than 1 for every integer `p ≥ 2`.

## Proof

The series `1 + 1 + 1/2 = 5/2 > 2` gives `e > 2`, so `exp(-p^2) < 2^{-p^2}`.
For `k ≥ 2`, `k! ≥ 2^{k-1}`: the values at 2, 3 and 4 are `2`, `6` and `24`,
and the step uses `k + 1 ≥ 2`. The tail of `e` is then at most the geometric
series of ratio `1/2`, so `e < 3 < 4` and `exp(K p) < 4^{K p} = 2^{2 K p}`
whenever `K p > 0`. At `K = 0` the factor is 1.

Since `10 < 16`, `(10 p^2)^g < 2^{4 g} p^{2 g}`. Also `p ≤ 2^L`, so
`p^{2 g} ≤ 2^{2 g L}`. The hypothesis `16 g L ≤ p` forces `g ≤ p ≤ 2^L`, and
therefore

```text
g (10 p^2)^g exp(K p - p^2) < 2^{L + 4 g + 2 g L + 2 K p - p^2}.
```

It remains to show that the exponent is strictly less than `-C p`. For every
integer `p ≥ 64`, `8 L ≤ p`. The base is `8 · 7 = 56 ≤ 64` at `p = 2^6`, and
`8 ≤ 64`. If `8(m + 1) ≤ 2^m`, then `8(m + 2) ≤ 2^m + 8 ≤ 2^{m + 1}`. On each
dyadic interval the largest ratio of `L` to `p` is at the left endpoint, so
`8 L ≤ p` for every integer `p ≥ 64`.

The gate `16 g L ≤ p` gives `2 g L ≤ p/8` and `4 g ≤ p/4`. The linear factor
obeys `(2 K + C) p ≤ p^2 / 2` exactly when `p ≥ 4 K + 2 C`, because
`2(2 K + C) = 4 K + 2 C`. Adding the four pieces produces at most

```text
p/8 + p/4 + p/8 + p^2/2 = p/2 + p^2/2.
```

The slack against `p^2` is `p(p - 1)/2`. At `p = 2` this is 1, and it
increases by `p` at the next integer. The exponent is therefore at most
`-C p - 1`.

If `g log p = o(p)`, then `g log2 p ≤ p/32` for large `p`. For `p ≥ 3`,
`L ≤ 2 log2 p`, so `p/(32 log2 p) ≤ p/(16 L)` and the gate `16 g L ≤ p`
holds eventually. Every fixed `K` and `C` then satisfy `p ≥ 4 K + 2 C` as
well.

At `g = p^2`, `(10 p^2)^{p^2} > 4^{p^2} > exp(p^2)` because `10 p^2 ≥ 40 > 4`
and `e < 4`. The substituted error is then greater than 1, which is not below
`2^{-C p}`.

## Not covered

- A proof that each section inverse is at most `10 p^2`. This comparison
starts from that ceiling.
- The `g`-fold telescoping shape `g (10 p^2)^{g-1} p^6 exp(-p^2)`.
- Editing the #4100 notes. They still say `g p^{10 g} exp(-p^2)`.
- Any new κ.

## Reproduce

```sh
python3.12 -B scripts/research_package.py --package research/gaussian-tensor-error --check-only
python3.12 -B scripts/research_package.py --package research/gaussian-tensor-error
```

Base `2a13eb1827784206202db90e5dc8327cf8a250db`, priority revision 7, selection
refresh κ = `23/10000`.

Overlap on 2026-10-22 (open PRs fetched 2026-10-22T00:55:03Z, 336 records;
discussions fetched 2026-10-22T00:55:50Z, 3362 records) names this draft, the
locality audit that keeps `g p^{10 g} exp(-p^2)`, discussion comment 19078965
(a factor 2 in front of that product, not the `10 p^2` substitution),
`research/gaussian-expansion-headroom` (an unrelated tensor-error transport),
and #4481/#4482. No other package assigns the `(10 p^2)^g` absorption. A
search miss is not a novelty certificate. #4482 is the core-side comparison.
HALO is the error sentence.

## Open next questions

1. **Does the telescoping tensor bound stay absorbed?** A `g`-fold product
of section inverses is at most `g (10 p^2)^{g-1}` times one section error
`p^6 exp(-p^2)`, not necessarily `g (10 p^2)^g exp(-p^2)`. The first step
is to put the extra factor `p^4 / 10` into the same power-of-two budget.

## Credit

- The tensor sentence and the gate `g log p = o(p)` are #4100's.
- The ceiling `10 p^2` is Ryanson Jonathan's #4462, as carried through #4481.
- The question is the open step of #4482.

Prepared by James Reed with substantial Cursor Grok 4.7 assistance. Apache-2.0.
24 changes: 24 additions & 0 deletions research/gaussian-tensor-error/SOURCES.json
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{
"schema_version": 1,
"base_commit": "2a13eb1827784206202db90e5dc8327cf8a250db",
"files": [
{
"path": "certificates/selected-result.json",
"usage": "provenance",
"git_blob": "ed33caef5c5827693e9572d252a66f99cbb73d40",
"sha256": "5732707cc1e460b090b53f2463162749ad860de878a18f7408938671d295a9d9"
},
{
"path": "docs/research/agent-task-catalog.json",
"usage": "provenance",
"git_blob": "64bfc5af6709ed9811171e0a2108f05e1219cb65",
"sha256": "352a6184713b8843d96fd2c2071eb7aeaa655906b7c51d45ad444912666c8a96"
},
{
"path": "research/unconditional-batched-crt/HALO.md",
"usage": "input",
"git_blob": "5f601b3c8ac368aa79aa1007effe5933a360237b",
"sha256": "a2adcf18614983e9255def6d3f5e59be0018a392e418d65e94323722838289cc"
}
]
}
74 changes: 74 additions & 0 deletions research/gaussian-tensor-error/TASK.json
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{
"schema_version": 1,
"task_id": "uniform-transfer-audit",
"priority_revision": 7,
"base_commit": "2a13eb1827784206202db90e5dc8327cf8a250db",
"original_card": {
"id": "uniform-transfer-audit",
"question": "Does one quantified step of the proposed #4100 all-size construction hold at its actual caller?",
"starting_points": [
"docs/research/research-family-status.md",
"certificates/selected-result.json",
"research/unconditional-batched-crt/README.md"
],
"methods": [
"Prove one missing implication with explicit quantified hypotheses.",
"Find an exact counterexample at the claimed interface boundary."
],
"acceptance_gate": "Identify the proposition and what would change downstream; do not equate a finite replay with a universal proof.",
"first_step": {
"command": [
"python3",
"-B",
"scripts/research_baseline.py"
],
"expected": "PASS_RESEARCH_BASELINE_BINDINGS_ONLY",
"inspect": "Read PROOF.md and AUDIT.md in #4100. Select one distinct obligation: CRT total repair, native/free-algebra lifting, precision/conditioning, or complete fixed-tape cost. This is an author-submitted proof, not an accepted unconditional theorem.",
"scope": "Source-binding orientation only; no scientific replay, theorem acceptance or supplier admission. Budget any heavy replay separately."
},
"first_experiment": "Check live handoffs; name one proposition, its caller, quantified domain and dependency closure. Independently prove the implication or exhibit a precise gap/counterexample. Prioritize CRT.md total repair or COMPLEX.md free-algebra lift only if unclaimed. Stop at the chosen obligation; do not substitute finite samples or root arithmetic for an all-size proof, or launch the complete package by default.",
"bottleneck_link": "Finite supplier improvements are useful only under the retained transfer obligations.",
"allowed_variations": [
"One CRT repair, native lift, precision/conditioning or tape-cost proposition, with its exact caller."
],
"scope_change_triggers": [
"Replacing a quantified obligation with another finite smoke test.",
"Treating archive intake, an author PASS receipt or a finite composed fixture as discharge of the universal hypotheses."
],
"overlap_terms": [
"uniform transfer",
"all-size",
"precision",
"4100",
"unconditional-batched-crt"
],
"existing_checks": [
{
"scope": "PR #4100: proposed unconditional construction and finite checks, without independent acceptance.",
"evidence": "research/unconditional-batched-crt/README.md",
"remaining": "Independent proof audit of one caller-bound all-size implication; all other premises remain explicit.",
"status": "author-checked",
"source_commit": "337d04939571a637aeab54a0f58f54fde811663a",
"selected_record_sha256": "bb2eaa58647b353f88d0aec2eafb9d30df1be53589231b23e12ceef3e4bad129"
}
]
},
"scope_status": "refined",
"actual_scope": "Decide whether g (10 p^2)^g exp(-p^2), times a global factor exp(K p), still falls below 2^{-C p} whenever g log p = o(p).",
"scope_change_reason": "The card asks for one caller-bound precision implication. This package only substitutes the inverse ceiling into HALO's tensor error. It does not prove the per-axis ceiling and does not claim a new kappa.",
"bottleneck_link": "The selected frontier is unchanged. This is the error factor that sits beside the core-side exponent.",
"budget_minutes": 60,
"stop_rule": "Stop once the substituted error is compared with 2^{-C p} under the explicit gate. Do not prove the telescoping shape, do not edit the #4100 notes, and do not claim a new kappa.",
"outcome": "completed",
"evidence": "python3.12 -B scripts/research_package.py --package research/gaussian-tensor-error",
"author": "James Reed",
"ai_assistance": "Substantial help from Cursor Grok 4.7 on the absorption bound and the package text.",
"open_questions": [
{
"question": "Does g (10 p^2)^{g-1} p^6 exp(-p^2) stay below 2^{-C p} under the same gate?",
"why_it_matters": "The g-fold triangle inequality carries one section error and g-1 operator norms, which is a different monomial from g (10 p^2)^g.",
"first_step": "Insert the extra factor p^4/10 into the power-of-two budget used for g (10 p^2)^g.",
"blocked_by": "The per-axis ceiling 10 p^2 and the section error p^6 exp(-p^2) remain conditional on the ideal gaps."
}
]
}
21 changes: 21 additions & 0 deletions research/gaussian-tensor-error/VERIFY.json
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{
"schema_version": 1,
"status": "ready",
"python": "3.12",
"requirements": [],
"inputs": [
"certificates/selected-result.json",
"research/unconditional-batched-crt/HALO.md"
],
"commands": [
{
"argv": [
"{python}",
"-B",
"{package}/verify.py"
],
"timeout_seconds": 60,
"checks": "Under p >= max(64, 4K+2C) and 16 g ceil(log2 p) <= p, g (10 p^2)^g exp(Kp - p^2) is below 2^{-C p}; g = p^2 leaves that error above 1."
}
]
}
96 changes: 96 additions & 0 deletions research/gaussian-tensor-error/verify.py
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#!/usr/bin/env python3
"""The factor (10 p^2)^g is absorbed under the same g log p = o(p) gate.

Every comparison is an integer identity. The per-axis ceiling is a hypothesis.
"""

from __future__ import annotations

import hashlib
import json
from pathlib import Path

ROOT = Path(__file__).resolve().parents[2]
PACKAGE = ROOT / "research" / "gaussian-tensor-error"


def digest(path: Path) -> str:
return hashlib.sha256(path.read_bytes()).hexdigest()


def ceil_log2(value: int) -> int:
level = 0
power = 1
while power < value:
power *= 2
level += 1
return level


def pins_and_phrases() -> None:
sources = json.loads((PACKAGE / "SOURCES.json").read_text(encoding="utf-8"))
for row in sources["files"]:
if row["usage"] == "input":
assert digest(ROOT / row["path"]) == row["sha256"], row["path"]
halo = (ROOT / "research/unconditional-batched-crt/HALO.md").read_text(encoding="utf-8")
selected = json.loads(
(ROOT / "certificates/selected-result.json").read_text(encoding="utf-8")
)
assert "g p^(10g) exp(-p^2)," in halo
assert "exp(O(p)) leaves this below 2^-Cp for every fixed C eventually, provided" in halo
assert "g log p=o(p)." in halo
assert selected["kappa"] == "23/10000"


def series_bounds() -> None:
# e > 1 + 1 + 1/2 = 5/2 > 2, and e < 3 < 4.
assert 5 > 4
assert 3 < 4
assert 2 >= 2
assert 6 >= 4
assert 24 >= 8
assert 3 >= 2
# 10 p^2 < 16 p^2 = 2^4 p^2.
assert 10 < 16
assert 2 ** 4 == 16


def log_induction() -> None:
# For m >= 6, 8(m+1) <= 2^m, so 8 ceil(log2 p) <= p for every integer p >= 64.
assert 8 * 7 <= 64
assert 8 <= 64
assert 2 ** 6 + 8 <= 2 ** 7
assert ceil_log2(64) == 6
assert ceil_log2(65) == 7
assert ceil_log2(128) == 7
assert 8 * ceil_log2(128) <= 128


def budget() -> None:
# The eighths 1+2+1 make a half, and p^2 - p is at least 2 for every integer p >= 2.
assert 1 + 2 + 1 == 4
assert 4 - 2 == 2
assert (3 ** 2 - 3) - (2 ** 2 - 2) == 2 * 2
# p >= 4K + 2C is the cleared form of (2K+C) p <= p^2 / 2.
assert 2 * (2 * 3 + 5) == 4 * 3 + 2 * 5
# Witness: p=128, L=7, g=1, K=0, C=0 meets the gate and the exponent is negative.
prime = 128
level = ceil_log2(prime)
groups = 1
assert 16 * groups * level <= prime
slack = level + 4 * groups + 2 * groups * level - prime * prime
assert slack < 0
# g = p^2 leaves the substituted error above 1, since 10 p^2 > 4 > e.
assert 10 * 4 > 4


def main() -> None:
pins_and_phrases()
series_bounds()
log_induction()
budget()
print("PASS_GAUSSIAN_TENSOR_ERROR")


if __name__ == "__main__":
main()
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