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Absorb the telescoping factor (10 p^2)^{g-1} p^6 (no new κ) - #4485

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Mister-Meeseeks merged 1 commit into
CrocSwap:mainfrom
jwr404:research/gaussian-tensor-fold
Oct 22, 2026
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Mister-Meeseeks merged 1 commit into
CrocSwap:mainfrom
jwr404:research/gaussian-tensor-fold

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@jwr404

@jwr404 jwr404 commented Oct 22, 2026

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Question

#4484 absorbs g (10 p^2)^g exp(-p^2) when p ≥ max(64, 4K + 2C) and 16 g ceil(log2 p) ≤ p. A g-fold triangle inequality carries g - 1 inverse ceilings and one section error. Does g (10 p^2)^{g-1} p^6 exp(-p^2) stay below 2^{-C p} under that same gate?

Result

Let p ≥ 2, g ≥ 1, K ≥ 0 and C ≥ 0 be integers, and let L = ceil(log2 p). If p ≥ max(64, 4K + 2C) and 16 g L ≤ p, then

g (10 p^2)^{g-1} p^6 exp(K p - p^2) < 2^{-C p}.

The case K = 0 is the monomial in the question. Relative to #4484 the extra factor is p^4 / 10, and it fits the same power-of-two budget: the exponent is at most -C p - 4. Whenever g log p = o(p), every fixed pair K, C meets the gate for large p. At g = p^2 the telescoping error is greater than 1 for every integer p ≥ 2.

Claim type: one absorption bound. No new κ. The ceiling 10 p^2 and the section error p^6 exp(-p^2) stay hypotheses. Replacing a ceiling by the approximant norm 10 p^2 + p^6 exp(-p^2) is not proved here, and the #4100 notes are unchanged.

This branch starts from canonical main. It does not replay #4484.

Test plan

python3.12 -B scripts/research_package.py --package research/gaussian-tensor-fold

PASS_GAUSSIAN_TENSOR_FOLD and outcome=completed on this machine. Maintainer replay has not been run.

Base 2a13eb1827784206202db90e5dc8327cf8a250db, priority revision 7, selection refresh κ = 23/10000.

Prepared by James Reed with substantial Cursor Grok 4.7 assistance.

Co-authored-by: Cursor <cursoragent@cursor.com>
@Mister-Meeseeks
Mister-Meeseeks merged commit bbde3b0 into CrocSwap:main Oct 22, 2026
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