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huyfififi
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Sep 14, 2026
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| ## STEP 2 | ||
| Linked Hashmapを使っても解けるみたい。順序を保持するhashmapに今の所1回しか登場していない文字と場所を記録し、すでに出現した文字をhashsetに記録する。2回目が現れたらhashmapから消して、最後にhashmapの中で一番最近のものを取得する。 |
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nit: dict の挿入順が保持されることを利用しているのですね。一番最近のものを取得というより、最初に挿入されたものを取得、とした方が誤解がないかもしれません。
| カウンターで頻度を取っておいて、次は先頭から頻度が1のものを探す。 | ||
| ```python | ||
| from collections import Counter | ||
| class Solution: |
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PEP8 に
Surround top-level function and class definitions with two blank lines.
とあるように、class と import 文の間に2つ空行を入れる方が一般的かと思います。
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