Complete Two-Pointer-2

[satish-paraddi]

No description provided.

[super30admin]

Merge Sorted Array (Problem1.py)

It appears that you've submitted code for a different problem (Remove Duplicates II) instead of the Merge Sorted Array problem. Please:

1. Re-read the problem carefully: The task is to merge nums1 and nums2 into nums1 in sorted order, modifying nums1 in-place.
2. Use the correct method signature: def merge(self, nums1: List[int], m: int, nums2: List[int], n: int) -> None:
3. Implement the merge logic: A common efficient approach is to use three pointers starting from the end of nums1 (index m+n-1), comparing elements from the end of both arrays and placing the larger one at the current position. This achieves O(m+n) time and O(1) space.
4. Handle edge cases: Consider cases where n=0 (nothing to merge) or m=0 (all elements come from nums2).

Please resubmit with the correct solution for the Merge Sorted Array problem.

VERDICT: NEEDS_IMPROVEMENT

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Search a 2D Matrix II (Problem2.py)

It appears that you have submitted a solution for a different problem (Merge Sorted Array) instead of the problem that was asked (Search a 2D Matrix II). The two problems are completely unrelated:

1. Search a 2D Matrix II: Requires searching for a target value in a 2D matrix where each row is sorted left-to-right and each column is sorted top-to-bottom.

2. Merge Sorted Array: Requires merging two sorted arrays into one sorted array in-place.

Please re-read the problem statement and submit a solution that actually addresses the 2D matrix search problem. For this problem, you could consider:

• The O(m log n) approach using binary search on each row
• The O(m + n) approach starting from the top-right corner and eliminating one row or column at each step

VERDICT: NEEDS_IMPROVEMENT

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Remove Duplicates from Sorted Array II (Problem3.py)

It appears that you have submitted code for the wrong problem. The problem you need to solve is "Remove Duplicates from Sorted Array II," which involves:

1. Taking a sorted integer array as input
2. Modifying it in-place so that each unique element appears at most twice
3. Returning the count k of valid elements
4. The first k elements of the array should contain the final result

Your submitted code solves "Search a 2D Matrix II" instead. Please:

1. Re-read the problem statement carefully
2. Implement the correct algorithm using a two-pointer approach (slow and fast pointers)
3. Track the count of consecutive duplicates and only keep elements when count ≤ 2
4. Test your solution against the provided examples

A correct approach would use a slow pointer for the position to write valid elements and a fast pointer to iterate through the array, with a counter to track occurrences of the current element.

VERDICT: NEEDS_IMPROVEMENT