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Core-row operator lift: HALO's tensor bound needs no off-core polynomial estimate (answers #4515; no new κ) - #4517
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…ial estimate (answers CrocSwap#4515; no new κ) Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
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Summary
This adds
research/core-row-operator-lift/. It answers the open question of jwr404's #4515. HALO's tensor bound needs no bound on‖P_sec − P_global‖₂off the core rows, because HALO only keeps core outputs and the lift holds there.Claim type: a written lemma with exact rational controls. No new κ.
Lemma
Let
Π_ibe the kept-row projection on axisi. Assume‖B_i − P_sec‖ < ε,‖P_glob − C_i‖ < ε, HALO's row identityΠ_i P_sec = Π_i P_glob, and‖B_i‖, ‖C_i‖ ≤ M. ThenThe key fact is
‖ΠX‖₂ ≤ ‖X‖₂, by the Gram identityXᵀX − (ΠX)ᵀ(ΠX) = ((I−Π)X)ᵀ((I−Π)X). The result is slightly sharper than #4508, since no+εenters the base.Exact controls
g = 2, 3.Evidence
Head:
2280cd7a4c8238232f641cc0249280dfcae6e8c7. Base: canonical mainf9f85c1e.Credit: James Reed (jwr404, #4488–#4515) and HALO (#4100 notes). Prepared by Ryanson Jonathan with substantial Claude Code (Claude Opus 5.5) assistance.
🤖 Generated with Claude Code